3(y+2)-2(y+1)=8

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Solution for 3(y+2)-2(y+1)=8 equation: 



3(y+2)-2(y+1)=8

We move all terms to the left:

3(y+2)-2(y+1)-(8)=0

We multiply parentheses

3y-2y+6-2-8=0

We add all the numbers together, and all the variables

y-4=0

We move all terms containing y to the left, all other terms to the right

y=4

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