3(y+2)-2(2y-2)=10

Solution for 3(y+2)-2(2y-2)=10 equation:

Simplifying
3(y + 2) + -2(2y + -2) = 10

Reorder the terms:
3(2 + y) + -2(2y + -2) = 10
(2 * 3 + y * 3) + -2(2y + -2) = 10
(6 + 3y) + -2(2y + -2) = 10

Reorder the terms:
6 + 3y + -2(-2 + 2y) = 10
6 + 3y + (-2 * -2 + 2y * -2) = 10
6 + 3y + (4 + -4y) = 10

Reorder the terms:
6 + 4 + 3y + -4y = 10

Combine like terms: 6 + 4 = 10
10 + 3y + -4y = 10

Combine like terms: 3y + -4y = -1y
10 + -1y = 10

Add '-10' to each side of the equation.
10 + -10 + -1y = 10 + -10

Combine like terms: 10 + -10 = 0
0 + -1y = 10 + -10
-1y = 10 + -10

Combine like terms: 10 + -10 = 0
-1y = 0

Solving
-1y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '-1'.
y = 0

Simplifying
y = 0