3(y+2)-1=10-(y-3)

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Solution for 3(y+2)-1=10-(y-3) equation: 



3(y+2)-1=10-(y-3)

We move all terms to the left:

3(y+2)-1-(10-(y-3))=0

We multiply parentheses

3y-(10-(y-3))+6-1=0



We calculate terms in parentheses: -(10-(y-3)), so:

10-(y-3)

determiningTheFunctionDomain
-(y-3)+10

We get rid of parentheses

-y+3+10

We add all the numbers together, and all the variables

-1y+13

Back to the equation:

-(-1y+13)



We add all the numbers together, and all the variables

3y-(-1y+13)+5=0

We get rid of parentheses

3y+1y-13+5=0

We add all the numbers together, and all the variables

4y-8=0

We move all terms containing y to the left, all other terms to the right

4y=8

y=8/4

y=2

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