3(y+2)-(y-5)=19

Solution for 3(y+2)-(y-5)=19 equation:

Simplifying
3(y + 2) + -1(y + -5) = 19

Reorder the terms:
3(2 + y) + -1(y + -5) = 19
(2 * 3 + y * 3) + -1(y + -5) = 19
(6 + 3y) + -1(y + -5) = 19

Reorder the terms:
6 + 3y + -1(-5 + y) = 19
6 + 3y + (-5 * -1 + y * -1) = 19
6 + 3y + (5 + -1y) = 19

Reorder the terms:
6 + 5 + 3y + -1y = 19

Combine like terms: 6 + 5 = 11
11 + 3y + -1y = 19

Combine like terms: 3y + -1y = 2y
11 + 2y = 19

Solving
11 + 2y = 19

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-11' to each side of the equation.
11 + -11 + 2y = 19 + -11

Combine like terms: 11 + -11 = 0
0 + 2y = 19 + -11
2y = 19 + -11

Combine like terms: 19 + -11 = 8
2y = 8

Divide each side by '2'.
y = 4

Simplifying
y = 4