3(y+2)+2=7(y-1)+9

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Solution for 3(y+2)+2=7(y-1)+9 equation: 



3(y+2)+2=7(y-1)+9

We move all terms to the left:

3(y+2)+2-(7(y-1)+9)=0

We multiply parentheses

3y-(7(y-1)+9)+6+2=0



We calculate terms in parentheses: -(7(y-1)+9), so:

7(y-1)+9

We multiply parentheses

7y-7+9

We add all the numbers together, and all the variables

7y+2

Back to the equation:

-(7y+2)



We add all the numbers together, and all the variables

3y-(7y+2)+8=0

We get rid of parentheses

3y-7y-2+8=0

We add all the numbers together, and all the variables

-4y+6=0

We move all terms containing y to the left, all other terms to the right

-4y=-6

y=-6/-4

y=1+1/2

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