3(y+2)+2(y-5)=

Solution for 3(y+2)+2(y-5)= equation:

Simplifying
3(y + 2) + 2(y + -5) = 0

Reorder the terms:
3(2 + y) + 2(y + -5) = 0
(2 * 3 + y * 3) + 2(y + -5) = 0
(6 + 3y) + 2(y + -5) = 0

Reorder the terms:
6 + 3y + 2(-5 + y) = 0
6 + 3y + (-5 * 2 + y * 2) = 0
6 + 3y + (-10 + 2y) = 0

Reorder the terms:
6 + -10 + 3y + 2y = 0

Combine like terms: 6 + -10 = -4
-4 + 3y + 2y = 0

Combine like terms: 3y + 2y = 5y
-4 + 5y = 0

Solving
-4 + 5y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 5y = 0 + 4

Combine like terms: -4 + 4 = 0
0 + 5y = 0 + 4
5y = 0 + 4

Combine like terms: 0 + 4 = 4
5y = 4

Divide each side by '5'.
y = 0.8

Simplifying
y = 0.8