3(y+2)+2(y-3)-1=15

Solution for 3(y+2)+2(y-3)-1=15 equation:

Simplifying
3(y + 2) + 2(y + -3) + -1 = 15

Reorder the terms:
3(2 + y) + 2(y + -3) + -1 = 15
(2 * 3 + y * 3) + 2(y + -3) + -1 = 15
(6 + 3y) + 2(y + -3) + -1 = 15

Reorder the terms:
6 + 3y + 2(-3 + y) + -1 = 15
6 + 3y + (-3 * 2 + y * 2) + -1 = 15
6 + 3y + (-6 + 2y) + -1 = 15

Reorder the terms:
6 + -6 + -1 + 3y + 2y = 15

Combine like terms: 6 + -6 = 0
0 + -1 + 3y + 2y = 15
-1 + 3y + 2y = 15

Combine like terms: 3y + 2y = 5y
-1 + 5y = 15

Solving
-1 + 5y = 15

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 5y = 15 + 1

Combine like terms: -1 + 1 = 0
0 + 5y = 15 + 1
5y = 15 + 1

Combine like terms: 15 + 1 = 16
5y = 16

Divide each side by '5'.
y = 3.2

Simplifying
y = 3.2