3(y+2)+15=-3(y-3)+6y

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Solution for 3(y+2)+15=-3(y-3)+6y equation: 



3(y+2)+15=-3(y-3)+6y

We move all terms to the left:

3(y+2)+15-(-3(y-3)+6y)=0

We multiply parentheses

3y-(-3(y-3)+6y)+6+15=0



We calculate terms in parentheses: -(-3(y-3)+6y), so:

-3(y-3)+6y

We add all the numbers together, and all the variables

6y-3(y-3)

We multiply parentheses

6y-3y+9

We add all the numbers together, and all the variables

3y+9

Back to the equation:

-(3y+9)



We add all the numbers together, and all the variables

3y-(3y+9)+21=0

We get rid of parentheses

3y-3y-9+21=0

We add all the numbers together, and all the variables

12!=0

There is no solution for this equation

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