3(y+12)=4(2-y)

Solution for 3(y+12)=4(2-y) equation:

3(y+12)=4(2-y)

We move all terms to the left:

3(y+12)-(4(2-y))=0

We add all the numbers together, and all the variables

3(y+12)-(4(-1y+2))=0

We multiply parentheses

3y-(4(-1y+2))+36=0


We calculate terms in parentheses: -(4(-1y+2)), so:

4(-1y+2)

We multiply parentheses

-4y+8

Back to the equation:

-(-4y+8)


We get rid of parentheses

3y+4y-8+36=0

We add all the numbers together, and all the variables

7y+28=0

We move all terms containing y to the left, all other terms to the right

7y=-28

y=-28/7

y=-4