3(y+1)=7y-21

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Solution for 3(y+1)=7y-21 equation: 



3(y+1)=7y-21

We move all terms to the left:

3(y+1)-(7y-21)=0

We multiply parentheses

3y-(7y-21)+3=0

We get rid of parentheses

3y-7y+21+3=0

We add all the numbers together, and all the variables

-4y+24=0

We move all terms containing y to the left, all other terms to the right

-4y=-24

y=-24/-4

y=+6

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