3(y+1)=5(y-3)+8

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Solution for 3(y+1)=5(y-3)+8 equation: 



3(y+1)=5(y-3)+8

We move all terms to the left:

3(y+1)-(5(y-3)+8)=0

We multiply parentheses

3y-(5(y-3)+8)+3=0



We calculate terms in parentheses: -(5(y-3)+8), so:

5(y-3)+8

We multiply parentheses

5y-15+8

We add all the numbers together, and all the variables

5y-7

Back to the equation:

-(5y-7)



We get rid of parentheses

3y-5y+7+3=0

We add all the numbers together, and all the variables

-2y+10=0

We move all terms containing y to the left, all other terms to the right

-2y=-10

y=-10/-2

y=+5

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