3(y+1)=4y-1

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Solution for 3(y+1)=4y-1 equation: 



3(y+1)=4y-1

We move all terms to the left:

3(y+1)-(4y-1)=0

We multiply parentheses

3y-(4y-1)+3=0

We get rid of parentheses

3y-4y+1+3=0

We add all the numbers together, and all the variables

-1y+4=0

We move all terms containing y to the left, all other terms to the right

-y=-4

y=-4/-1

y=+4

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