3(y+1)=4y+21

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Solution for 3(y+1)=4y+21 equation:



3(y+1)=4y+21
We move all terms to the left:
3(y+1)-(4y+21)=0
We multiply parentheses
3y-(4y+21)+3=0
We get rid of parentheses
3y-4y-21+3=0
We add all the numbers together, and all the variables
-1y-18=0
We move all terms containing y to the left, all other terms to the right
-y=18
y=18/-1
y=-18

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