3(y+1)=2(y-2)-6

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Solution for 3(y+1)=2(y-2)-6 equation:


Simplifying
3(y + 1) = 2(y + -2) + -6

Reorder the terms:
3(1 + y) = 2(y + -2) + -6
(1 * 3 + y * 3) = 2(y + -2) + -6
(3 + 3y) = 2(y + -2) + -6

Reorder the terms:
3 + 3y = 2(-2 + y) + -6
3 + 3y = (-2 * 2 + y * 2) + -6
3 + 3y = (-4 + 2y) + -6

Reorder the terms:
3 + 3y = -4 + -6 + 2y

Combine like terms: -4 + -6 = -10
3 + 3y = -10 + 2y

Solving
3 + 3y = -10 + 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.
3 + 3y + -2y = -10 + 2y + -2y

Combine like terms: 3y + -2y = 1y
3 + 1y = -10 + 2y + -2y

Combine like terms: 2y + -2y = 0
3 + 1y = -10 + 0
3 + 1y = -10

Add '-3' to each side of the equation.
3 + -3 + 1y = -10 + -3

Combine like terms: 3 + -3 = 0
0 + 1y = -10 + -3
1y = -10 + -3

Combine like terms: -10 + -3 = -13
1y = -13

Divide each side by '1'.
y = -13

Simplifying
y = -13

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