3(y+1)=-y+4

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Solution for 3(y+1)=-y+4 equation: 



3(y+1)=-y+4

We move all terms to the left:

3(y+1)-(-y+4)=0

We add all the numbers together, and all the variables

3(y+1)-(-1y+4)=0

We multiply parentheses

3y-(-1y+4)+3=0

We get rid of parentheses

3y+1y-4+3=0

We add all the numbers together, and all the variables

4y-1=0

We move all terms containing y to the left, all other terms to the right

4y=1

y=1/4

y=1/4

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