3(y+1)-3=2(x-3)+1

Solution for 3(y+1)-3=2(x-3)+1 equation:

Simplifying
3(y + 1) + -3 = 2(x + -3) + 1

Reorder the terms:
3(1 + y) + -3 = 2(x + -3) + 1
(1 * 3 + y * 3) + -3 = 2(x + -3) + 1
(3 + 3y) + -3 = 2(x + -3) + 1

Reorder the terms:
3 + -3 + 3y = 2(x + -3) + 1

Combine like terms: 3 + -3 = 0
0 + 3y = 2(x + -3) + 1
3y = 2(x + -3) + 1

Reorder the terms:
3y = 2(-3 + x) + 1
3y = (-3 * 2 + x * 2) + 1
3y = (-6 + 2x) + 1

Reorder the terms:
3y = -6 + 1 + 2x

Combine like terms: -6 + 1 = -5
3y = -5 + 2x

Solving
3y = -5 + 2x

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '3'.
y = -1.666666667 + 0.6666666667x

Simplifying
y = -1.666666667 + 0.6666666667x