3(y+1)+y2=5(y-1)+5

Solution for 3(y+1)+y2=5(y-1)+5 equation:

3(y+1)+y2=5(y-1)+5

We move all terms to the left:

3(y+1)+y2-(5(y-1)+5)=0

We add all the numbers together, and all the variables

y^2+3(y+1)-(5(y-1)+5)=0

We multiply parentheses

y^2+3y-(5(y-1)+5)+3=0


We calculate terms in parentheses: -(5(y-1)+5), so:

5(y-1)+5

We multiply parentheses

5y-5+5

We add all the numbers together, and all the variables

5y

Back to the equation:

-(5y)


We add all the numbers together, and all the variables

y^2-2y+3=0

a = 1; b = -2; c = +3;
Δ = b2-4ac
Δ = -22-4·1·3
Δ = -8
Delta is less than zero, so there is no solution for the equation