3(y+1)+7y=4(y+1)5

Solution for 3(y+1)+7y=4(y+1)5 equation:

3(y+1)+7y=4(y+1)5

We move all terms to the left:

3(y+1)+7y-(4(y+1)5)=0

We add all the numbers together, and all the variables

7y+3(y+1)-(4(y+1)5)=0

We multiply parentheses

7y+3y-(4(y+1)5)+3=0


We calculate terms in parentheses: -(4(y+1)5), so:

4(y+1)5

We multiply parentheses

20y+20

Back to the equation:

-(20y+20)


We add all the numbers together, and all the variables

10y-(20y+20)+3=0

We get rid of parentheses

10y-20y-20+3=0

We add all the numbers together, and all the variables

-10y-17=0

We move all terms containing y to the left, all other terms to the right

-10y=17

y=17/-10

y=-1+7/10