3(y+1)+3=7(y-2)

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Solution for 3(y+1)+3=7(y-2) equation:


Simplifying
3(y + 1) + 3 = 7(y + -2)

Reorder the terms:
3(1 + y) + 3 = 7(y + -2)
(1 * 3 + y * 3) + 3 = 7(y + -2)
(3 + 3y) + 3 = 7(y + -2)

Reorder the terms:
3 + 3 + 3y = 7(y + -2)

Combine like terms: 3 + 3 = 6
6 + 3y = 7(y + -2)

Reorder the terms:
6 + 3y = 7(-2 + y)
6 + 3y = (-2 * 7 + y * 7)
6 + 3y = (-14 + 7y)

Solving
6 + 3y = -14 + 7y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-7y' to each side of the equation.
6 + 3y + -7y = -14 + 7y + -7y

Combine like terms: 3y + -7y = -4y
6 + -4y = -14 + 7y + -7y

Combine like terms: 7y + -7y = 0
6 + -4y = -14 + 0
6 + -4y = -14

Add '-6' to each side of the equation.
6 + -6 + -4y = -14 + -6

Combine like terms: 6 + -6 = 0
0 + -4y = -14 + -6
-4y = -14 + -6

Combine like terms: -14 + -6 = -20
-4y = -20

Divide each side by '-4'.
y = 5

Simplifying
y = 5

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