3(y+1)+2y=12

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Solution for 3(y+1)+2y=12 equation: 



3(y+1)+2y=12

We move all terms to the left:

3(y+1)+2y-(12)=0

We add all the numbers together, and all the variables

2y+3(y+1)-12=0

We multiply parentheses

2y+3y+3-12=0

We add all the numbers together, and all the variables

5y-9=0

We move all terms containing y to the left, all other terms to the right

5y=9

y=9/5

y=1+4/5

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