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3(x4)=2x(6+x)
We move all terms to the left:
3(x4)-(2x(6+x))=0
We add all the numbers together, and all the variables
3x4-(2x(x+6))=0
We add all the numbers together, and all the variables
3x^4-(2x(x+6))=0
We calculate terms in parentheses: -(2x(x+6)), so:We do not support expression: x^4
2x(x+6)
We multiply parentheses
2x^2+12x
Back to the equation:
-(2x^2+12x)
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