3(x2+5)-6=(9x+18)/3

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Solution for 3(x2+5)-6=(9x+18)/3 equation: 



3(x2+5)-6=(9x+18)/3

We move all terms to the left:

3(x2+5)-6-((9x+18)/3)=0

We add all the numbers together, and all the variables

3(+x^2+5)-((9x+18)/3)-6=0

We multiply parentheses

3x^2-((9x+18)/3)+15-6=0

We multiply all the terms by the denominator


3x^2*3)-((9x+18)+15*3)-6*3)=0

We add all the numbers together, and all the variables

3x^2*3)-((9x+18)=0

Wy multiply elements

9x^3=0

We do not support expression: x^3

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