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3(x2)+5x=6x-16
We move all terms to the left:
3(x2)+5x-(6x-16)=0
We add all the numbers together, and all the variables
3x^2+5x-(6x-16)=0
We get rid of parentheses
3x^2+5x-6x+16=0
We add all the numbers together, and all the variables
3x^2-1x+16=0
a = 3; b = -1; c = +16;
Δ = b2-4ac
Δ = -12-4·3·16
Δ = -191
Delta is less than zero, so there is no solution for the equation
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