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3(x1/2-8=x+4)
We move all terms to the left:
3(x1/2-8-(x+4))=0
Domain of the equation: 2-8-(x+4))!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
-(x+4))!=6
x∈R
3(x1=0
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