3(x1/2)=5(x+7/2)+4x-1

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Solution for 3(x1/2)=5(x+7/2)+4x-1 equation: 


x in (-oo:+oo)

3*((x^1)/2) = 5*(x+7/2)+4*x-1 // - 5*(x+7/2)+4*x-1

3*((x^1)/2)-(5*(x+7/2))-(4*x)+1 = 0

3*(x/2)-5*(x+7/2)-4*x+1 = 0

(3*x)/2-5*(x+7/2)-4*x+1 = 0

(-5*2*(x+7/2))/2+(3*x)/2+(-4*2*x)/2+(1*2)/2 = 0

3*x-5*2*(x+7/2)-4*2*x+1*2 = 0

2-7*x-8*x-35 = 0

2-15*x-35 = 0

-15*x-33 = 0

(-15*x-33)/2 = 0

(-15*x-33)/2 = 0 // * 2

-15*x-33 = 0

-15*x-33 = 0 // + 33

-15*x = 33 // : -15

x = 33/(-15)

x = -11/5

x = -11/5

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