3(x-8)+x=2(x+3)-5

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Solution for 3(x-8)+x=2(x+3)-5 equation: 



3(x-8)+x=2(x+3)-5

We move all terms to the left:

3(x-8)+x-(2(x+3)-5)=0

We add all the numbers together, and all the variables

x+3(x-8)-(2(x+3)-5)=0

We multiply parentheses

x+3x-(2(x+3)-5)-24=0



We calculate terms in parentheses: -(2(x+3)-5), so:

2(x+3)-5

We multiply parentheses

2x+6-5

We add all the numbers together, and all the variables

2x+1

Back to the equation:

-(2x+1)



We add all the numbers together, and all the variables

4x-(2x+1)-24=0

We get rid of parentheses

4x-2x-1-24=0

We add all the numbers together, and all the variables

2x-25=0

We move all terms containing x to the left, all other terms to the right

2x=25

x=25/2

x=12+1/2

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