3(x-7)+4(8-2x)-7=-4(x+2)-6

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Solution for 3(x-7)+4(8-2x)-7=-4(x+2)-6 equation: 



3(x-7)+4(8-2x)-7=-4(x+2)-6

We move all terms to the left:

3(x-7)+4(8-2x)-7-(-4(x+2)-6)=0

We add all the numbers together, and all the variables

3(x-7)+4(-2x+8)-(-4(x+2)-6)-7=0

We multiply parentheses

3x-8x-(-4(x+2)-6)-21+32-7=0



We calculate terms in parentheses: -(-4(x+2)-6), so:

-4(x+2)-6

We multiply parentheses

-4x-8-6

We add all the numbers together, and all the variables

-4x-14

Back to the equation:

-(-4x-14)



We add all the numbers together, and all the variables

-5x-(-4x-14)+4=0

We get rid of parentheses

-5x+4x+14+4=0

We add all the numbers together, and all the variables

-1x+18=0

We move all terms containing x to the left, all other terms to the right

-x=-18

x=-18/-1

x=+18

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