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3(x-6)=5(4x-19)
We move all terms to the left:
3(x-6)-(5(4x-19))=0
We multiply parentheses
3x-(5(4x-19))-18=0
We calculate terms in parentheses: -(5(4x-19)), so:We get rid of parentheses
5(4x-19)
We multiply parentheses
20x-95
Back to the equation:
-(20x-95)
3x-20x+95-18=0
We add all the numbers together, and all the variables
-17x+77=0
We move all terms containing x to the left, all other terms to the right
-17x=-77
x=-77/-17
x=4+9/17
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