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3(x-6)-8x=(2x+1)
We move all terms to the left:
3(x-6)-8x-((2x+1))=0
We add all the numbers together, and all the variables
-8x+3(x-6)-((2x+1))=0
We multiply parentheses
-8x+3x-((2x+1))-18=0
We calculate terms in parentheses: -((2x+1)), so:We add all the numbers together, and all the variables
(2x+1)
We get rid of parentheses
2x+1
Back to the equation:
-(2x+1)
-5x-(2x+1)-18=0
We get rid of parentheses
-5x-2x-1-18=0
We add all the numbers together, and all the variables
-7x-19=0
We move all terms containing x to the left, all other terms to the right
-7x=19
x=19/-7
x=-2+5/7
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