3(x-6)+8(x-4)=x+3x-2

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Solution for 3(x-6)+8(x-4)=x+3x-2 equation: 



3(x-6)+8(x-4)=x+3x-2

We move all terms to the left:

3(x-6)+8(x-4)-(x+3x-2)=0

We add all the numbers together, and all the variables

3(x-6)+8(x-4)-(4x-2)=0

We multiply parentheses

3x+8x-(4x-2)-18-32=0

We get rid of parentheses

3x+8x-4x+2-18-32=0

We add all the numbers together, and all the variables

7x-48=0

We move all terms containing x to the left, all other terms to the right

7x=48

x=48/7

x=6+6/7

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