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3(x-6)+(12-3x)=-6
We move all terms to the left:
3(x-6)+(12-3x)-(-6)=0
We add all the numbers together, and all the variables
3(x-6)+(-3x+12)-(-6)=0
We add all the numbers together, and all the variables
3(x-6)+(-3x+12)+6=0
We multiply parentheses
3x+(-3x+12)-18+6=0
We get rid of parentheses
3x-3x+12-18+6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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