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3(x-6)(x+9)=0
We multiply parentheses ..
3(+x^2+9x-6x-54)=0
We multiply parentheses
3x^2+27x-18x-162=0
We add all the numbers together, and all the variables
3x^2+9x-162=0
a = 3; b = 9; c = -162;
Δ = b2-4ac
Δ = 92-4·3·(-162)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-45}{2*3}=\frac{-54}{6} =-9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+45}{2*3}=\frac{36}{6} =6 $
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