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3(x-5)=6-2(x-1)
We move all terms to the left:
3(x-5)-(6-2(x-1))=0
We multiply parentheses
3x-(6-2(x-1))-15=0
We calculate terms in parentheses: -(6-2(x-1)), so:We get rid of parentheses
6-2(x-1)
determiningTheFunctionDomain -2(x-1)+6
We multiply parentheses
-2x+2+6
We add all the numbers together, and all the variables
-2x+8
Back to the equation:
-(-2x+8)
3x+2x-8-15=0
We add all the numbers together, and all the variables
5x-23=0
We move all terms containing x to the left, all other terms to the right
5x=23
x=23/5
x=4+3/5
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