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3(x-5)=5-(4x-15)
We move all terms to the left:
3(x-5)-(5-(4x-15))=0
We multiply parentheses
3x-(5-(4x-15))-15=0
We calculate terms in parentheses: -(5-(4x-15)), so:We get rid of parentheses
5-(4x-15)
determiningTheFunctionDomain -(4x-15)+5
We get rid of parentheses
-4x+15+5
We add all the numbers together, and all the variables
-4x+20
Back to the equation:
-(-4x+20)
3x+4x-20-15=0
We add all the numbers together, and all the variables
7x-35=0
We move all terms containing x to the left, all other terms to the right
7x=35
x=35/7
x=5
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