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3(x-5)=5(2x-1)
We move all terms to the left:
3(x-5)-(5(2x-1))=0
We multiply parentheses
3x-(5(2x-1))-15=0
We calculate terms in parentheses: -(5(2x-1)), so:We get rid of parentheses
5(2x-1)
We multiply parentheses
10x-5
Back to the equation:
-(10x-5)
3x-10x+5-15=0
We add all the numbers together, and all the variables
-7x-10=0
We move all terms containing x to the left, all other terms to the right
-7x=10
x=10/-7
x=-1+3/7
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