3(x-5)=4x+33

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Solution for 3(x-5)=4x+33 equation: 



3(x-5)=4x+33

We move all terms to the left:

3(x-5)-(4x+33)=0

We multiply parentheses

3x-(4x+33)-15=0

We get rid of parentheses

3x-4x-33-15=0

We add all the numbers together, and all the variables

-1x-48=0

We move all terms containing x to the left, all other terms to the right

-x=48

x=48/-1

x=-48

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