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3(x-5)=4(2x-10)
We move all terms to the left:
3(x-5)-(4(2x-10))=0
We multiply parentheses
3x-(4(2x-10))-15=0
We calculate terms in parentheses: -(4(2x-10)), so:We get rid of parentheses
4(2x-10)
We multiply parentheses
8x-40
Back to the equation:
-(8x-40)
3x-8x+40-15=0
We add all the numbers together, and all the variables
-5x+25=0
We move all terms containing x to the left, all other terms to the right
-5x=-25
x=-25/-5
x=+5
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