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3(x-5)=2-7(x-3)
We move all terms to the left:
3(x-5)-(2-7(x-3))=0
We multiply parentheses
3x-(2-7(x-3))-15=0
We calculate terms in parentheses: -(2-7(x-3)), so:We get rid of parentheses
2-7(x-3)
determiningTheFunctionDomain -7(x-3)+2
We multiply parentheses
-7x+21+2
We add all the numbers together, and all the variables
-7x+23
Back to the equation:
-(-7x+23)
3x+7x-23-15=0
We add all the numbers together, and all the variables
10x-38=0
We move all terms containing x to the left, all other terms to the right
10x=38
x=38/10
x=3+4/5
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