3(x-5)=2(x-4)+9

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Solution for 3(x-5)=2(x-4)+9 equation: 



3(x-5)=2(x-4)+9

We move all terms to the left:

3(x-5)-(2(x-4)+9)=0

We multiply parentheses

3x-(2(x-4)+9)-15=0



We calculate terms in parentheses: -(2(x-4)+9), so:

2(x-4)+9

We multiply parentheses

2x-8+9

We add all the numbers together, and all the variables

2x+1

Back to the equation:

-(2x+1)



We get rid of parentheses

3x-2x-1-15=0

We add all the numbers together, and all the variables

x-16=0

We move all terms containing x to the left, all other terms to the right

x=16

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