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3(x-5)=2(2x+9)
We move all terms to the left:
3(x-5)-(2(2x+9))=0
We multiply parentheses
3x-(2(2x+9))-15=0
We calculate terms in parentheses: -(2(2x+9)), so:We get rid of parentheses
2(2x+9)
We multiply parentheses
4x+18
Back to the equation:
-(4x+18)
3x-4x-18-15=0
We add all the numbers together, and all the variables
-1x-33=0
We move all terms containing x to the left, all other terms to the right
-x=33
x=33/-1
x=-33
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