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3(x-5)=2(2x+2)
We move all terms to the left:
3(x-5)-(2(2x+2))=0
We multiply parentheses
3x-(2(2x+2))-15=0
We calculate terms in parentheses: -(2(2x+2)), so:We get rid of parentheses
2(2x+2)
We multiply parentheses
4x+4
Back to the equation:
-(4x+4)
3x-4x-4-15=0
We add all the numbers together, and all the variables
-1x-19=0
We move all terms containing x to the left, all other terms to the right
-x=19
x=19/-1
x=-19
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