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3(x-5)-8=-3(-7x+9)-2x
We move all terms to the left:
3(x-5)-8-(-3(-7x+9)-2x)=0
We multiply parentheses
3x-(-3(-7x+9)-2x)-15-8=0
We calculate terms in parentheses: -(-3(-7x+9)-2x), so:We add all the numbers together, and all the variables
-3(-7x+9)-2x
We add all the numbers together, and all the variables
-2x-3(-7x+9)
We multiply parentheses
-2x+21x-27
We add all the numbers together, and all the variables
19x-27
Back to the equation:
-(19x-27)
3x-(19x-27)-23=0
We get rid of parentheses
3x-19x+27-23=0
We add all the numbers together, and all the variables
-16x+4=0
We move all terms containing x to the left, all other terms to the right
-16x=-4
x=-4/-16
x=1/4
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