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3(x-5)-4(x-4)=-2(x-11)
We move all terms to the left:
3(x-5)-4(x-4)-(-2(x-11))=0
We multiply parentheses
3x-4x-(-2(x-11))-15+16=0
We calculate terms in parentheses: -(-2(x-11)), so:We add all the numbers together, and all the variables
-2(x-11)
We multiply parentheses
-2x+22
Back to the equation:
-(-2x+22)
-1x-(-2x+22)+1=0
We get rid of parentheses
-1x+2x-22+1=0
We add all the numbers together, and all the variables
x-21=0
We move all terms containing x to the left, all other terms to the right
x=21
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