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3(x-5)-(2+x)=3
We move all terms to the left:
3(x-5)-(2+x)-(3)=0
We add all the numbers together, and all the variables
3(x-5)-(x+2)-3=0
We multiply parentheses
3x-(x+2)-15-3=0
We get rid of parentheses
3x-x-2-15-3=0
We add all the numbers together, and all the variables
2x-20=0
We move all terms containing x to the left, all other terms to the right
2x=20
x=20/2
x=10
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