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3(x-5)+7=2(x-2)+4
We move all terms to the left:
3(x-5)+7-(2(x-2)+4)=0
We multiply parentheses
3x-(2(x-2)+4)-15+7=0
We calculate terms in parentheses: -(2(x-2)+4), so:We add all the numbers together, and all the variables
2(x-2)+4
We multiply parentheses
2x-4+4
We add all the numbers together, and all the variables
2x
Back to the equation:
-(2x)
x-8=0
We move all terms containing x to the left, all other terms to the right
x=8
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