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3(x-5)+6=2(5x+3)
We move all terms to the left:
3(x-5)+6-(2(5x+3))=0
We multiply parentheses
3x-(2(5x+3))-15+6=0
We calculate terms in parentheses: -(2(5x+3)), so:We add all the numbers together, and all the variables
2(5x+3)
We multiply parentheses
10x+6
Back to the equation:
-(10x+6)
3x-(10x+6)-9=0
We get rid of parentheses
3x-10x-6-9=0
We add all the numbers together, and all the variables
-7x-15=0
We move all terms containing x to the left, all other terms to the right
-7x=15
x=15/-7
x=-2+1/7
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