3(x-5)+3=12+2(x-1)

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Solution for 3(x-5)+3=12+2(x-1) equation: 



3(x-5)+3=12+2(x-1)

We move all terms to the left:

3(x-5)+3-(12+2(x-1))=0

We multiply parentheses

3x-(12+2(x-1))-15+3=0



We calculate terms in parentheses: -(12+2(x-1)), so:

12+2(x-1)

determiningTheFunctionDomain
2(x-1)+12

We multiply parentheses

2x-2+12

We add all the numbers together, and all the variables

2x+10

Back to the equation:

-(2x+10)



We add all the numbers together, and all the variables

3x-(2x+10)-12=0

We get rid of parentheses

3x-2x-10-12=0

We add all the numbers together, and all the variables

x-22=0

We move all terms containing x to the left, all other terms to the right

x=22

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