3(x-5)+2(3x+1)=41

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Solution for 3(x-5)+2(3x+1)=41 equation:


Simplifying
3(x + -5) + 2(3x + 1) = 41

Reorder the terms:
3(-5 + x) + 2(3x + 1) = 41
(-5 * 3 + x * 3) + 2(3x + 1) = 41
(-15 + 3x) + 2(3x + 1) = 41

Reorder the terms:
-15 + 3x + 2(1 + 3x) = 41
-15 + 3x + (1 * 2 + 3x * 2) = 41
-15 + 3x + (2 + 6x) = 41

Reorder the terms:
-15 + 2 + 3x + 6x = 41

Combine like terms: -15 + 2 = -13
-13 + 3x + 6x = 41

Combine like terms: 3x + 6x = 9x
-13 + 9x = 41

Solving
-13 + 9x = 41

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '13' to each side of the equation.
-13 + 13 + 9x = 41 + 13

Combine like terms: -13 + 13 = 0
0 + 9x = 41 + 13
9x = 41 + 13

Combine like terms: 41 + 13 = 54
9x = 54

Divide each side by '9'.
x = 6

Simplifying
x = 6

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