3(x-5)+15=3(2+4x)-(6x+2)

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Solution for 3(x-5)+15=3(2+4x)-(6x+2) equation: 



3(x-5)+15=3(2+4x)-(6x+2)

We move all terms to the left:

3(x-5)+15-(3(2+4x)-(6x+2))=0

We add all the numbers together, and all the variables

3(x-5)-(3(4x+2)-(6x+2))+15=0

We multiply parentheses

3x-(3(4x+2)-(6x+2))-15+15=0



We calculate terms in parentheses: -(3(4x+2)-(6x+2)), so:

3(4x+2)-(6x+2)

We multiply parentheses

12x-(6x+2)+6

We get rid of parentheses

12x-6x-2+6

We add all the numbers together, and all the variables

6x+4

Back to the equation:

-(6x+4)



We add all the numbers together, and all the variables

3x-(6x+4)=0

We get rid of parentheses

3x-6x-4=0

We add all the numbers together, and all the variables

-3x-4=0

We move all terms containing x to the left, all other terms to the right

-3x=4

x=4/-3

x=-1+1/3

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