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3(x-5)+11=-2(x-3)
We move all terms to the left:
3(x-5)+11-(-2(x-3))=0
We multiply parentheses
3x-(-2(x-3))-15+11=0
We calculate terms in parentheses: -(-2(x-3)), so:We add all the numbers together, and all the variables
-2(x-3)
We multiply parentheses
-2x+6
Back to the equation:
-(-2x+6)
3x-(-2x+6)-4=0
We get rid of parentheses
3x+2x-6-4=0
We add all the numbers together, and all the variables
5x-10=0
We move all terms containing x to the left, all other terms to the right
5x=10
x=10/5
x=2
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